List of typos, omissions, proofing errors for:
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THE MATHEMATICS CALENDAR 2008
May 14: The problem should read: Determine the maximum y-coordinate where this curve's tangent is zero.
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THE MATHEMATICS CALENDAR 2007.
January 5: Option (5) should read: 5) No rectangles are trapezoids.
March 30: The problem should read: x is a rational number. What must x equal for this triplet to represent the sides of a right triangle.
Dec 6: The following equation is missing: 4x^2 +20x + 4y^2 - 48y = -165
Footnote 8 for BRANES ON THE BRAINThe big tests at CERN are coming should read "8The Large Hadron Collider(LHC) is the newest addition to CERN. Its 27km circumference makes it the world's largest superconductivity installation. Superconductivity allows certain materials to conduct electricity without the loss of energy. This usually takes place at extremely low temperatures. LHD is located at at average depth of 100m underground and will operate at around 300° below room temperature, which is colder than outer space. LHD now occupies the 27 km circle which had been where the earlier LEP collider was located."
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MORE OF OF MATHEMATICS
page 63- The number in the square that appears at the intersection of the 4th column and 3rd row should be 12.
page 159- Correct a typo in the DAY NUMBERS chart, the number corresponding to Saturday's should be 0, not 7.
Revise the steps as follows for example
August 27, 1990.
1) Take the last two figures in the year, 90. This
number will be used in both step 2 and 5.
2) Divided the 2-digit number from step 1 by the number 4, and
ignore its remainder. 90÷4= 22 (and the remainder
2 you ignore).
3) Go to the month chart and find the month's number. It is 3.
4) From the desired date, take the day's number. For our example
date it is 27.
5) From the century chart find the century number for the desired
year. For 1990 its is 0.
6) Now, add together the numbers from steps 1, 2, 3, 4,5.
Divide this sum by 7, namely 90+22+3+27+0 = 142 So, 142÷7 = 20 plus remainder 2.
Use the remainder number to look up the day of the week in the DAY NUMBERS chart. For 2 it is Wednesday.
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MATH-A-DAY
3rd printing May 2004
page 217- solution for FEB 18's last sentence should read " n(n - 3)/2 = 65 --> n =13. So the polygon has 13 sides."
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THE MATHEMATICS CALENDAR 2006.
January 19: Should read: " F+4 This hexadecimal sum is ___in base ten."
April 28: Should read: " A stone-like object dropped in 8 feet of water in a cylindrical vat with a 4' diameter floats in the vat. The stone-like object raised the water level to 0.43 inches. Water weighs about 62.205 lbs per cubic foot. What is the stone-like object s weight to the nearest pound?"
May 21: 3(square root of 2) should read 7(square root of 2): The statement should read: "(9/49) of this cone's volume is ___pi cubic units."
September 10: Should read: " 50! ends in 2+__zeros."
December 23: The angles in the diagams should be changed as follows: 70 degrees is a degrees. 110 degrees should be 180 degrees minus a degrees.
December 30: The first sentence should read: "Two friends flew with 105 lbs. of baggage together.".
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THE MATHEMATICS CALENDAR 2005.
January 4-
The word "thousands" in the last sentence should be
"hundreds".
January 16- The last sentence should read "Its
volume is ___(sq. root of 2)/3."
April 2-
The number 6 in the equation should be a negative 6.
April's story-The 2nd to the last sentence should read
"In fact, a square is a convex quadrilateral."
May 10-The questions should read: "Find the radius of the circle."
June 20- The point of tangency on the side of length 4 is also a bisection point. Two marks on each side of this tangent point were left off.
July 16- The 40° should be deleted
July 30- After the last 15 in the problem, the square root of 2 should follow it, so it reads: 15(square root of2)
August 9-- The final sentence should read: "Find the largest value for its width."
Page 26 under FOOTNOTES & ADDITIONAL INFORMATION: In footnote 8 delete ".com" after the word "Hotbits".
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